## Integration & Antiderivative of 1/(ax+b)

The antiderivative of 1/(ax+b) is 1/a ln|ax+b| + C where ln|x| = loge|x| and C is a constant. In this post, we will learn how to find the antiderivative of 1/(ax+b), that is, how to integrate 1 divided by ax+b. The antiderivative formula of 1/(ax+b), that is, the integral of 1/(ax+b) is given by ∫1/(ax+b) … Read more